## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Criteria for Similarity of Triangles

Triangles | Chapter 6 Exercise 6.3 Criteria for Similarity of Triangles:  Criteria for similarity of Triangles: 1.   AA or AAA similarity criterion 2.   SAS similarity criterion 3.  SSS similarity criterion Solution: Detailed explanation is given in the below image and YouTube video. Next Post

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 16

Triangles | Chapter 6 Exercise 6.3 Question 16:  If AD and PM are medians of triangles ABC and PQR, respectively where ∆ABC ~ ∆PQR. Prove that Solution: Detailed explanation is given in the below image and YouTube video.

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 15

Triangles | Chapter 6 Exercise 6.3 Question 15:  A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Solution: Detailed explanation is given in the below image and YouTube video. […]

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 14

Triangles | Chapter 6 Exercise 6.3 Question 14:  Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR.   Show that ∆ABC ~ ∆PQR Solution: Detailed explanation is given in the below image and YouTube video. Next Post

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 13

Triangles | Chapter 6 Exercise 6.3 Question 13:  D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA 2 = CB.CD. Solution: Detailed explanation is given in the below image and YouTube video. Next Post

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 12

Triangles | Chapter 6 Exercise 6.3 Question 12:  Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of ∆PQR (see the given figure). Show that ∆ABC ∼ ∆PQR. Solution: Detailed explanation is given in the below image and YouTube video. Next Post

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 11

Triangles | Chapter 6 Exercise 6.3 Question 11:  In the following figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that ∆ABD ∼ ∆ECF Solution: Detailed explanation is given in the below image and YouTube video. Next […]

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 10

Triangles | Chapter 6 Exercise 6.3 Question 10:  CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ∆ABC and ∆EFG respectively. If ∆ABC ∼ ∆FEG, Show that: (i)  (ii) ∆DCB ∼ ∆HGE (iii) ∆DCA ∼ ∆HGF Solution: Detailed explanation is given […]

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 9

Triangles | Chapter 6 Exercise 6.3 Question 9:  In the following figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that:  (i) ∆ABC ∼ ∆AMP            (ii)      Solution: Detailed explanation is given in the below image and YouTube video. Next Post

## NCERT Solutions Class 10 Maths – Triangles | Chapter 6 Exercise – 6.3 Question 8

Triangles | Chapter 6 Exercise 6.3 Question 8:  E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ∆ABE ∼ ∆CFB. Solution: Detailed explanation is given in the below image and YouTube video. Next Post